<PRE><B>Question 775735</B>
Given: (16-5i)*(-2-i)
Let
(1) P = (16-5i)*(-2-i)
All you need to do is FOIL the binomials of (1) to get
(2) P = 16*(-2) + 16*(-i) -5i*(-2) -5i*(-i) or
(3) P = -32 - 16*i +10i + 5i^2 or
because i^2 = -1 we get
(4) P = -32 - 16*i +10i - 5 or
(5) P = -32 - 6i - 5 or
(6) P = -37 - 6i
Answer: (16-5i)*(-2-i) =  -37 - 6i





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