Question 775701
This is in a form we call vertex form.

Y = (x-h)^2 + k   where (h,k) is the vertex.

Given that, we know that the vertex is (4, -3)


If we can find out the two y-intercepts [or zeroes] we can connect the dots into a parabola and graph.

Solve for x.

y + 3 = (x-4)^2 

+-sqrt(y+3) = x -4 

+- sqrt(y+3) + 4 = x

Put y =0,

4 +- sqrt(3) =  2.3 and 6.7


So we have (2.3,0), (4,-3) (6.7,0)

Connect and we've got it.