Question 775686
{{{16x-16=-1/x}}}
{{{16x-16+1/x=0}}}
{{{(16x^2-16x+1)/x=0}}}
{{{16x^2-16x+1}}}=0
{{{x = (-b +- sqrt( b^2-4*a*c ))/(2*a) }}}
{{{a=16}}}, {{{b=-16}}}, {{{c=1}}}
{{{x = (-(-16) +- sqrt( (-16)^2-4*16*1 ))/(2*16) }}}
{{{x= (16 +- sqrt( 192 ))/32}}}
{{{x= (16 +- 8sqrt( 3))/32}}}
{{{x= (2 +- sqrt( 3))/4}}}
Answer: {{{x= (2 +- sqrt( 3))/4}}}