Question 775580
Let the angle of elevation be θ.
 
We have a right angled triangle with an opposite of 300.5 ft. (306 - 5.5) and an adjacent of 400 ft.  Recalling SOH CAH TOA, tanθ = O/A.
tan(θ) = 300.5/400.
θ = tan^-1(300.5/400).
θ = 36.9°.