Question 775487
{{{(16x-9)/(8x+3)=2-8/x}}} common denominator on the right side is x so
{{{(16x-9)/(8x+3)=2x/x-8/x}}}
{{{(16x-9)/(8x+3)=(2x-8)/x}}} now multiply across
{{{x(16x-9)=(8x+3)(2x-8)}}} simplify
{{{16x^2-9x=16x^2+6x-64x-24}}} subtract 16x^2 from each side
{{{-9x=6x-64x-24}}}
{{{-9x=-58x-24}}} add 58x to each side
{{{49x=-24}}} divide each side by 49
{{{x=-24/49}}}