Question 775337
{{{x^2-4x-60=0}}}


{{{x^2-4x+4 -64=0}}}


{{{(x+2)^2-64=0}}}

{{{(x+2)^2=64}}}


Take the squareroot

(x+2)= +/- {{{sqrt(64)}}}

x=-2 +/- 8

x=-10 OR 6