Question 66617
Multiply:

n^2-n-20     n^2+5n
--------  * -------
  2n^2       n^2-25

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Factor where possible to get:

[(n-5)(n+4)/2n^2 ]* [n(n+5)/(n-5)(n+5)]

Cancel factors that are common to numerator and denominator to get:

=[(n+4)]/[2]

Cheers,
Stan H.