Question 66624
Solve:
{{{x^2+6x+6 = 0}}} Since this is not factorable, you can use the quadratic formula to solve for x:
{{{x = (-b+-sqrt(b^2-4ac))/2a}}} in this problem, a = 1, b = 6, and c = 6
{{{x = (-6+-sqrt(6^2-4(1)(6)))/2(1)}}} Simplify this.
{{{x = (-6+-sqrt(36-24))/2}}}
{{{x = (-6+-sqrt(12))/2}}}
{{{x = (-6+-2sqrt(3))/2}}}
{{{x1 = -3+sqrt(3)}}}
{{{x2 = -3-sqrt(3)}}}