Question 775266
the formula of the circle:

{{{(x-h)^2+(y-k)^2=r^2}}} where {{{h}}} and {{{k}}} are the {{{x}}} and {{{y }}}coordinates of the center of the circle, and {{{r}}} is the radius

so,the equation of the circle with center ({{{-6}}},{{{2}}}) and radius {{{(2sqrt(3)/3)}}} is:

{{{(x+6)^2+(y-2)^2=(2sqrt(3)/3)^2}}}

{{{(x+6)^2+(y-2)^2=(4*3)/9}}}

{{{(x+6)^2+(y-2)^2=4/3}}}