Question 775167
{{{(X^2-9x)/(4x-24)}}} * {{{(x^2-36)/(4x^2-36x)}}} * {{{(8x)/(x^2+5x-6)}}}
We can do a lot of factoring here
{{{(x(x-9))/(4(x-6))}}} * {{{((x-6)(x+6))/(4x(x-9))}}} * {{{(8x)/((x+6)(x-1))}}}
Cancel (x-9), (x-6), (x+6), 4x cancels in to 8x, middle fraction is eliminated
{{{(x)/(4)}}} *  {{{2/((x-1))}}} = {{{(2x)/(4(x-1))}}} = 
cancel 2 in to 4, leaving only:
{{{(x)/(2(x-1))}}}
:
Do you understand what we did here, any questions?