Question 774980
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There are a number of different possibilities since you did not specify a right cylinder.  You didn't specify a circular (as opposed to an elliptical) cylinder either, but circular is implied by the fact that you specified a diameter.  Assuming a right cylinder, the intersection will either be a rectangle that is taller than it is wide, or a straight line in the case where the intersection of the plane and the cylinder is tangent to the side of the cylinder.  In the case of an oblique cylinder, it could be a rectangle, an ellipse, a half-ellipse, or a single point depending on whether the plane intersects both bases, neither base, one base, or is tangent to one of the bases.


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
<font face="Math1" size="+2">Egw to Beta kai to Sigma</font>
My calculator said it, I believe it, that settles it
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