Question 66598
I will not do your assignment paper persay ... but I will tell you some interesting facts.
y = youngster .... a = adults
Pairs are counted as Adult Pairs:
initial time: 1y ~> 0 (a) pairs
1 month: 1a ~> 1 (a)pair (give birth to 1y)
2 months: 1a1y ~> 1 (a)pair
3 months: 2a1y ~> 2 (a)pairs
4 months: 3a2y ~> 3 (a)pairs
5 months: 5a3y ~> 5 (a)pairs
6 months: 8a5y ~> 8 (a)pairs
7 months: 13a8y ~> 13 (a)pairs
8 months: 21a13y ~> 21 (a)pairs
9 months: 34a21y ~> 34 (a)pairs
10 months: 55a34y ~> 55 (a)pairs
11 months: 89a55y ~> 89 (a)pairs
12 months: 144a89y ~> 144 (a)pairs
0,1,1,2,3,5,8,13,21,34,55,89,144....
See a pattern or do you already know the series? It is the Fibonacci Series where the sum of the two previous numbers is the equivalent to the third. This series gives birth to a number that is thought as sacred or golden (a.k.a. the golden number.)
Define as one of the Fib. numbers as {{{x2}}} and the previous number to be {{{x1}}}.
As {{{x2}}} approaches infinity: {{{x2}}}/{{{x1}}} = Golden Number = 1.618033....
{{{sum((x2)/(x1),x1 = 0,infinity)}}} = {{{(1 + sqrt(5))/2)}}} = 1.618033....