<PRE><B>Question 774703</B>
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The sum of the interior angles is *[tex \LARGE (n\ -\ 2)\,\cdot\,180]


The sum of the exterior angles is *[tex \LARGE 360]


The ratio of the sum of the angles is the same as the ratio of the individual angles, so:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \frac{(n\ -\ 2)\,\cdot\,180}{360}\ =\ \frac{n\ -\ 2}{2}]


But the ratio is 3:1, so


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \frac{n\ -\ 2}{2}\ =\ \frac{3}{1}]


Solve for *[tex \LARGE n]


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
&lt;font face=&quot;Math1&quot; size=&quot;+2&quot;&gt;Egw to Beta kai to Sigma&lt;/font&gt;
My calculator said it, I believe it, that settles it
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