Question 774692

{{{y=X^2}}}..... the basic upward opening parabola

since you have {{{x^2}}}, always will be two {{{x}}} have the same {{{y}}} value

example:
if {{{x=1}}} => {{{y=(1)^2}}}=> {{{y=1}}}
if {{{x=-1}}} => {{{y=(-1)^2}}}=> {{{y=1}}}

or
if {{{x=2}}} => {{{y=(2)^2}}}=> {{{y=4}}}
if {{{x=-2}}} => {{{y=(-2)^2}}}=> {{{y=4}}}

it happens to be {{{x=0}}} first, and {{{0}}} is neither positive nor negative, so the lowest point of this parabola is the vertex which is at ({{{0}}},{{{0}}})
and parabola touches {{{x-axis, as {{{y-axis}}} as well, only ones
 
{{{ graph( 600, 600, -10, 10, -10, 10, x^2) }}}