Question 66562
FInd the equation of the line that is equidistant from the points A=(1,4) and B=(-3,2). Write your equation in general form.
LET ANY POINT 'P' ON THE LINE BE (X,Y)
PA=PB......GIVEN
PA^2=PB^2
(X-1)^2+(Y-4)^2=(X+3)^2+(Y-2)^2
X^2-2X+1+Y^2-8Y+16=X^2+6X+9+Y^2-4Y+4
6X+9-4Y+4+2X-1+8Y-16=0
8X+4Y-4=0
2X+Y-1=0