<PRE><B>Question 774457</B>
The sum of their distances when they meet will be 69 km.  Do you want to focus on a number line, or do you want to focus on time quantity?  


Try looking at time quantity.  May travels less time than Sheila, because May began her trip LATER than Sheila.  Note that the difference between 1 pm and 1:15 pm is (1/4) of an hour.  ... THINK how this seems correct.  
...
Let h = time that May travels.  This means that h+1/4 is the time in hours that Sheila travels.  ..., again, THINK how this seems correct.
...
READY?




Make a data table.


Rower_________speed,km/hour ______time__________distance, km.
Sheila_________12________________h+1/4_________{{{12(h+1/4)}}}
May____________10_________________h_____________{{{10h}}}
TOTAL___________________________________________{{{69}}}



Can you study all that and understand the process?

Can you use the information in the data table and see the equation to form?

Can you solve the equation for h?  

Finally, use h to get the time of the day that they meet?</PRE>