Question 774404
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Divide the opposite of the coordinate on *[tex \LARGE x] by the coordinate on *[tex \LARGE y] to find the slope of the graph of the given equation.  Determine the negative reciprocal of that slope to find the slope of any graph perpendicular to the graph of the given line.


Use the point-slope form:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ y\ -\ y_1\ =\ m(x\ -\ x_1) ]


where *[tex \Large \left(x_1,y_1\right)] are the coordinates of the given point and *[tex \Large m] is the calculated slope.


Rearrange the result into either *[tex \LARGE Ax\ +\ By\ =\ C] or *[tex \LARGE ax\ +\ by\ +\ c\ =\ 0] depending on your particular instructor's definition of General Form.  Generally, by convention, the equation is written so that *[tex \LARGE A\ \geq\ 0], and frequently it is specified that A, B, and C must be integers.  Again, these requirements are variable and you need to follow your instructor's guidance.


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
<font face="Math1" size="+2">Egw to Beta kai to Sigma</font>
My calculator said it, I believe it, that settles it
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