Question 774327
{{{8/(y-3) - 7/y=
8y/(y^2-3y) - (7y-21)/(y^2-3y)=(y+21)/(y^2-3y)}}}




{{{5/(y^2-3y) + 2/y=5/(y^2-3y) + (2y-6)/(y^2-3y)=(2y-1)/(y^2-3y)}}}