Question 774197
In an equilateral triangle the altitude h = {{{(sqrt(3)a)/2}}} where a is the length of the side

6= {{{sqrt(3)*a/2}}}

{{{sqrt(3)a= 2*6}}}

a= {{{(2*6)/sqrt(3)}}}


a= {{{(2*sqrt(3)*sqrt(3)*3)/sqrt(3)}}}

{{{a=6sqrt(3)}}}

Area of triangle = 1/2 * base * height

base = a={{{6sqrt(3)}}}

h=6

area = 1/2 * 6*6{{{sqrt(3)}}}

=18{{{sqrt(3)}}}