Question 774136
{{{x}}}= the first integer
So the sum of the 5 consecutive integers is
{{{x+(x+1)+(x+2)+(x+3)+(x+4)=x+x+1+x+2+x+3+x+4=x+x+x+x+x+1+2+3+4=(x+x+x+x+x)+(1+2+3+4)=5x+10=5(x+2)}}}
{{{x+2}}}= an integer, actually, the third of the 5 consecutive integers,
so {{{5(x+2)}}} is a multiple of 5.