Question 774099
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No solution.  That is because *[tex \LARGE x\ \ ] and *[tex \LARGE \ \ X\ \ ]are NOT the same thing.


Now, if what you REALLY meant was that your system of linear equations is:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ 3x\ +\ 2y\ =\ 8]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ y\ =\ x\ -\ 1]


That is a horse of a completely different color.  Since the second equation gives you an expression in *[tex \LARGE x] that is equal to, and that means "the same as", *[tex \LARGE y], you can replace *[tex \LARGE y] anywhere you see it with that expression in *[tex \LARGE x], namely *[tex \LARGE x\ -\ 1], thus:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ 3x\ +\ 2(x\ -\ 1)\ =\ 8]


Now all you have to do is solve the single variable equation for *[tex \LARGE x]


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
<font face="Math1" size="+2">Egw to Beta kai to Sigma</font>
My calculator said it, I believe it, that settles it
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