Question 774045
You have
(1) x = e^(ln2^5)
Take the natural logarithm of each side to get
(2) ln(x) = (ln2^5)*ln(e)
Since ln(e) = 1 we have
(3) ln(x) = ln(2^5)
Now take the inverse log of each to get
(4) x = 2^5 or
(5) x = 32
Answer: e^(ln2^5) = 32