Question 773994
if A+B=90;SinA=3/4 then secB=?
<pre>
Since sine = {{{opposite/hypotenus}}}, draw a right triangle
with opposite side the numerator of 3/4, which is 3, and 
a hypotenuse which is the denominator of 3/4, which is 4:

{{{drawing(1000/3,400,-1,4,-1,5, triangle(0,0,sqrt(7),0,sqrt(7),3),

line(0,0,sqrt(7),0), line(sqrt(7),0,sqrt(7),3), line(sqrt(7),3,0,0),
locate(2.8,1.5,3), locate(.8,1.5,4), locate(.3,.3,A),locate(2.5,2.8,B) 





)}}} {{{matrix(18,1,

The,secant,is,hypotenuse/adjacent,and,the,adjacent,of,B,is, the,opposite,of,A, or,3,therefore,sec(B)=4/3)}}}

A simpler way to do it is this way: 

sin(A) = cos(B) = 3/4, and sec(B) = [reciprocal of cos(B)] = 4/3

{Edwin</pre>