Question 773965
x^2-2((k)+(1/k))x+3=0

discriminant = d = (-2((k)+(1/k)))^2-4(1)(3) =

4(k^2+2+1/k^^2) -12

=  4k^2+8+4/k^2 -12

=  4k^2+4/k^2 -4

= 4(k^2+1/k^2 -1)

= 4 ((k-1/k)^2 +1) >0  

Then the equation has 2 real solutions



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