Question 773693
Let y = length of one side of the square.

The square of side y cut into four equal rectangles:
If {{{2y+2(y/4)=80}}}, then what is {{{y^2}}}?


{{{drawing(370,370,0,20,0,20,
line(4,12,12,12),
line(4,12,4,4),
line(12,12,12,4),
line(4,4,12,4),
line(6,4,6,12),
line(8,4,8,12),
line(10,4,10,12),
locate(3.5,8,y),
locate(4.6,3.9,y/4)
)}}}

Steps, algebraic
{{{(2+1/2)y=80}}}
{{{(5/2)y=80}}}
{{{y=(2/5)80}}}
{{{highlight(y=32)}}}


Area of Square: {{{y*y=32^2=highlight(1024)}}} {{{cm^2}}}