Question 773652
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{{{x^2 - 8*x*y + 16*y^2 - 25}}}
You can see that the 1st 3 terms are in the form of a^2 - 2ab + b^2, which is
(a - b)^2
So it can be first written as
{{{(x - 4*y)^2 - 25}}}
Now this is of the form a^2 - b^2, which is (a+b)*(a-b)
{{{(x - 4*y)^2 - 25}}} =
{{{(x - 4*y)^2 - 5^2}}} =
{{{(x - 4*y +5)*(x - 4*y - 5)}}} which is the final factorization.
Hope you got it :)
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