Question 773500
(1)  The two numbers are as 2n+1 and 2n+3.


{{{(2n+1)^2+(2n+3)^2=103+(2n+1)(2n+3)}}}
{{{4n^2+4n+1+4n^2+12n+9=103+4n^2+8n+3}}}
{{{8n^2+16+10=4n^2+8n+106}}}
{{{4n^2+8n-96=0}}}
{{{n^2+2n-24=0}}}


{{{(n-4)(n+6)=0}}}
We use the POSITIVE solution to n.
{{{n=4}}}.


The numbers are {{{2*4+1=9}}}
and
{{{2*4+3=11}}}
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The numbers are 9 and 11
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