Question 773480
Let the numbers be 'x' and 'y'.
Let 'x' be the larger number.
 
So x - y = 36 ------------(1)
   4y - x = 6 ------------(2)

Rearranging equation 2 we get 
   -x + 4y = 6
    x - y  = 36 ----------(1)
  -------------
Adding the above two equations we have
   3y = 42
or y = 14

From equation(1) x - y = 36
              or x = 36 + y = 36 + 14 = 50

So the numbers are 50 and 14.
 
check: Condition 1 :   50 - 14 = 36
       Condition 2 :   4*14 - 50 = 56 - 50 = 6