Question 772845
what is the focus of the conic section 
12x+y^2-14y+1=0
complete the square
(y^2-14y+49)-49+1=-12x
(y^2-14y+49)-48=-12x
(y^2-7)^2=-12x+48
(y^2-7)^2=-12(x-4)
This is an equation of a parabola that opens leftward:
Its basic equation: (y-k)^2=-4p(x-h), (h,k)=(x,y) coordinates of the vertex
For given parabola:
vertex: (4,7)
axis of symmetry: y=7
4p=12
p=3
focus: (1,7)