Question 8485
 Solve: |3x+7|<7

 A direct way to solve |ax-b| < c if a > 0 and c > 0
 by converting it to  -c < ax-b < c 
 or equivalently (b-c)/a < x < (b+c)/a

 Here, a =3, b = -7, c = 7,
 So,    -14/3 < x < 0 or  the interval (-14/3, 0)

 Kenny