Question 773143
{{{log(x+2)+log(x-1)=log(70)}}}..write left side as single log


{{{log((x+2)(x-1))=log(70)}}}.....if log same, then

{{{(x+2)(x-1)=70}}} is same too; now, solve for {{{x}}}

{{{x^2-x+2x-2=70}}} 

{{{x^2+x-2-70=0}}} 

{{{x^2+x-72=0}}} ...write {{{x}}} as {{{9x-8x}}}

{{{x^2+9x-8x-72= 0}}}..group

{{{(x^2+9x)-(8x+72)= 0}}}...factor

{{{x(x+9)-8(x+9)= 0}}}

{{{(x-8)(x+9)= 0}}}

solutions:

if {{{(x-8)= 0}}}=> {{{x=8}}}

if {{{(x+9)= 0}}}=> {{{x=-9}}}

so, we need only => {{{x=8}}}.....your answer