Question 66478
7(3x+4) = 8(2x+5) + 13  expand:

7*3x+7*4=8*2x+8*5+13 multiplyiing the terms, we get

21x+28=16x+40+13  subtract 16x and 28 from both sides of the equation

21x-16x-28+28=16x-16x-28+40+13  collecting like terms

5x=25
x=5

ck

7(3*5+4)=8(2*5+5)+13

7(19)=8(15)+13
133=120+13
133=133


Hope this helps-----ptaylor