Question 773008
"Consecutive factors"?

n and n+1 as factors?


n(n+1)=48
n^2+n=48
n^2+n-48=0

Check discriminant:  {{{(1^2-4*(-48))<>0}}}
n will be nonwhole, but irrational.
Did you leave something off the problem?

Maybe {{{xy=48}}} for some two whole number factors x and y.
These are your only positive possibilities to get product 48:
{{{1*48}}}
{{{2*24}}}
{{{3*12}}}
{{{6*8}}}________This might be what you want, if consecutive EVEN integers.