Question 772968
{{{(2x+1)/3-(10x+1)/6 = 1 }}}

we have to eliminate the denominator

LCM = 6

multiply the whole equation by 6

{{{((2x+1)*6)/3-((10x+1)*6)/6 = 6*1 }}}


{{{(2x+1)*2-(10x+1)*1 = 6 }}}


4x+2-10x-1=6

-6x=5

x= -5/6