<PRE><B>Question 772960</B>
let the catchup distance be x

time taken by MIla is x/50

time taken by Husband = x/70

diffrenece in their starting time = 10 mins = 10/60 = 1/6 hours

time taken by Mila - time taken by husband = 1/6 hours

x/50 -x/70 =1/6

70x-50x= 70*50/6

20x= 70*50/6

x= (70*50)/(6*20)

x= 29.17

He will catch up after he drives 29.17 km.



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