<PRE><B>Question 66396</B>
A plane took 1 hour longer to travel 560 miles on the first portion of a flight than it took to fly 480 miles on the second portion. If the speed was the same for each portion, what was the flying time for the second part of the trip?
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1st portion DATA:
distance=560 ; time=x+1 hrs ; rate=d/r= 560/(x+1) mph
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2nd portion DATA:
distance= 480 ; time = x hrs ; rate= d/r = 480/x mph
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EQuATION:
 1st rate = 2nd rate
560/(x+1)=480/x
560x=480x+480
80x=480
x=6 hrs (flying time for the 2nd part of the trip)
Cheers,
Stan H.</PRE>