Question 772815
(3/y - 3/x)/ [(x^2 - y^2)/ xy]

Work on the numerator first

3/y - 3/x = (3x - 3y)/xy = 3(x - y)/(xy)

The denominator:

[(x - y)(x + y)/(xy)]

Put them together in fraction form

[3(x - y)/(xy)]  * [(xy)/(x - y)(x + y)]

Cancel like terms from the numerator and denominator

The result is:

3/(x + y) <=== answer key

Hope it helps you!

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