Question 772794
Find all solutions, real and imaginary, of the equation: 
4t^4-13t^2=12
4t^4-13t^2-12=0
let u=t^2
u^2=t^4
..
4u^2-13u-12=0
(u-4)(4u+3)=0
u=4=t^2
t^2=±√4=±2
or
u=-3/4=t^2
t^2=±√-3/4=±i√3/2

solutions: -2, 2, -i√3/2, i√3/2