Question 66410
Find the inverse {{{y^-1}}}of:
{{{y = 6-2x}}} Just swap the x and the y, then solve for y.
{{{x = 6-2y}}} Solve for y. Subtract 6 from both sides.
{{{x-6 = -2y}}} Divide both sides by -2.
{{{-x/2 + 3 = y}}} So, the inverse is:
{{{y^-1 = 3-x/2}}}

Check: Recall that: {{{f(f^-1)(x) = x}}}
{{{y(y^-1) = 6-2(3-x/2)}}} Simplify.
{{{y(y^-1) = 6-6+x}}}
{{{y(y^-1) = x}}}