Question 772646
The x^2 just means {{{x^2}}}.  That is how you write it using plain text.  


Solving this would first need combining the terms of x.
{{{x^2+5x+4=70}}}   ________(2x+3x=5x)
{{{x^2+5x+4-70=0}}}
{{{x^2+5x-66=0}}}


Can you factorize the left side?  
66=6*11
6+11=17
6-11=-5
11-6=5
-6-11=-17
Choice should be obvious.


{{{(x^2+5x-66)=highlight((x-6)(x+11)=0)}}}
Either {{{x-6=0}}} OR {{{x+11=0}}} so you have two solutions for x.....