Question 772608
Solve for x algebraically.

ln(2x+3)-ln(x-5)= 2

Here's what i have started.

ln(2x+3)/(x-5)=2

I'm not sure where to go past here.
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{{{ln((2x+3)/(x-5))=2 }}} Make it clear that it's the ln of the quotient.
{{{(2x+3)/(x-5) = e^2 }}}
e^2 is a constant.  Can you finish it?