Question 772550
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Eq (1):  *[tex \LARGE 2x\ -\ 5y\ =\ -18]


Eq (2):  *[tex \LARGE 3x\ +\ y\ =\ 7]


Solve Eq (2) for *[tex \LARGE y]


Eq (3):  *[tex \LARGE y\ =\ 7\ -\ 3x]


Substitute the RHS of Eq (3) in place of *[tex \LARGE y] in Eq (1)


Eq (4):  *[tex \LARGE 2x\ -\ 5(7\ -\ 3x)\ =\ -18]


Solve Eq (4) for *[tex \LARGE x], then substitute the value just discovered for *[tex \LARGE x] in place of *[tex \LARGE x] in either original equation.  Solve the single variable equation in *[tex \LARGE y] for *[tex \LARGE y]


Report the *[tex \LARGE x] and *[tex \LARGE y] values.


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
<font face="Math1" size="+2">Egw to Beta kai to Sigma</font>
My calculator said it, I believe it, that settles it
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