Question 66364
Divide:

x^2 + 2x - 15          x^2 - 25
-------------    /   ------------
     4x^2               2x - 10
:
Remember when dividing, you invert the dividing fraction, and multiply:
{{{(x^2 + 2x - 15)/(4x^2)}}} * {{{(2x - 10)/(x^2 - 25)}}}
:
You can do some major factoring here:
{{{((x+5)(x-3))/(4x^2)}}} * {{{(2(x - 5))/((x+5)(x-5))}}}
:
Cancel x+5, x-5, also the the 2 cancels into the 4, resulting in:
{{{(x-3)/(2x^2)}}}