Question 772239
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Use the mid-point formulas:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ x_m\ = \frac{x_1 + x_2}{2}] and


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ y_m\ = \frac{y_1 + y_2}{2}]


where *[tex \Large \left(x_1,y_1\right)] and *[tex \Large \left(x_2,y_2\right)] are the coordinates of the diameter end points to determine the ordered pair representing the center of the circle.


The radius of the circle is the distance from the center of the circle to either of the endpoints.  Use the distance formula modified:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ r^2\ =\ (x_1\ -\ x_2)^2\ +\ (y_1\ -\ y_2)^2]


where *[tex \Large \left(x_1,y_1\right)] and *[tex \Large \left(x_2,y_2\right)] are the coordinates of the center of the circle and one of the diameter end points to determine the square of the measure of the radius.


Then


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ (x\ -\ h)^2\ +\ (y\ -\ k)^2\ =\ r^2]


is the equation of a circle centered at *[tex \LARGE (h,\,k)] with radius *[tex \LARGE r].  All you have to do is plug in the numbers.


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
<font face="Math1" size="+2">Egw to Beta kai to Sigma</font>
My calculator said it, I believe it, that settles it
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