Question 771931
I have been stuck on this question for about 45 minutes can somebody please help me?
Problem :A bank contains 44 coins (nickels, dimes, and quarters).  There are twice as many dimes as nickels and 8 fewer nickels than quarters.  How much money is in the bank? Thank You!
<pre>

Alan didn't figure up the money, Nerdybill divided wrong and got 16
quarters instead of 17.

Let q = the number of quarters
</pre>
>>,,,8 fewer nickels than quarters...<< 
<pre>
So the number of nickels is q-8
</pre>
There are twice as many dimes as nickels
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So the number of dimes is 2×(the number of nickels) = 2(q-8)

The equation comes from

{{{(matrix(4,1,
The,number,of,quarters))}}}{{{""+""}}}{{{(matrix(4,1,
The,number,of,nickels))}}}{{{""+""}}}{{{(matrix(4,1,
The,number,of,dimes))}}} {{{""=""}}} {{{(matrix(5,1,
The,total,number,of,coins))}}}

So 

 q + (q-8) + 2(q-8) = 44

q + q - 8 + 2q - 16 = 44 

            4q - 24 = 44

                 4q = 68

                  q = 17 quarters

the number of nickels is q-8 = 17-8 = 9 nickels

the number of dimes = 2(q-8) = 2(17-8) = 2(9) = 18 dimes

17 quarters = $0.25(17) = $4.25
 9 nickels  = $0.05(9)  =   .45
18 dimes    = $0.10(18) =  1.80
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 total money            = $6.50                             

Edwin</pre>