Question 771931
A bank contains 44 coins (nickels, dimes, and quarters).  There are twice as many dimes as nickels and 8 fewer nickels than quarters.  How much money is in the bank?
.
Let q = number of quarters
then from "8 fewer nickels than quarters":
q-8 = number of nickels
and from "twice as many dimes as nickels"
2(q-8) = number of dimes
.
q + q-8 + 2(q-8) = 44
q + q-8 + 2q-16 = 44
4q -8 -16 = 44
4q -24 = 44
4q = 68
q = 16 
.
amount in bank:
.25q + .05(q-8) + .10(2(q-8)) 
.25(16) + .05(16-8) + .10(2(16-8)) 
.25(16) + .05(8) + .10(2(8)) 
.25(16) + .05(8) + .10(16) 
.25(16) + .05(8) + .10(16) 
4 + .40 + 1.60
$6.00