Question 66346
 x^2+6x+8/x^2+x-2 divided by x+4/2x+4
:
remember that when you divide you invert the dividing fraction and multiply:
 {{{(x^2+6x+8)/(x^2+x-2)}}} * {{{(2x+4)/(x+4)}}}
:
You can factor here:
{{{((x+4)(x+2))/((x+2)(x-1))}}} * {{{(2(x+2))/(x+4)}}}
:
Notice that you can cancel the (x+4)'s and the (x+2)'s, leaving us with:
{{{1/(x-1))}}} * x(x+2)
:
{{{(x(x+2))/(x-1))}}} is our results