Question 771771


({{{-1}}},{{{8}}}) =({{{x}}},{{{y}}}) 

so, exponentiation form  will be: 

{{{ y=a* b^x}}}

{{{ 8=a* b^-1}}}

and ({{{1}}},{{{2}}}) 

{{{ y=a* b^x}}}

{{{ 3=a* b^1}}}