Question 771781
an equation of the line satisfying the following condition:

passing through the {{{x-axis}}} at {{{-5}}} => passing through the point ({{{-5}}},{{{0}}})

 and has a slope of {{{m=4/3}}}

slope-intercept form of linear equation is {{{y=mx+b}}} where {{{m}}} is a slope and {{{b}}} is {{{y-intercept}}}

using given point we will have:

{{{0=(4/3)(-5)+b}}}.....solve for {{{b}}}

{{{0=-20/3+b}}}

{{{b=20/3}}}

{{{b=20/3}}}

then your equation is: {{{y=(4/3)x+20/3}}}


{{{ graph( 600, 600, -10, 10, -10, 10, (4/3)x+20/3) }}}