Question 771614
 

{{{y^2 + (x - 88)^2 = 400}}}

{{{y^2 + (x - 88)^2 = 20^2}}}......this is a circle {{{(y-k)^2+ (x - h)^2 = r^2}}}

as you can see, {{{h=88}}} and {{{k=0}}}; so, the center is at ({{{88}}},{{{0}}}) and radius is {{{r=20}}}


{{{ graph( 600, 600, -120,120, -120, 120, sqrt(-(x -88)^2+400),-sqrt(-(x -88)^2+ 400)) }}}